4-MMC (mephedrone) synthesis. Complete video tutorial.

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C10H11BrO + CH5N → C11H15NO + HBr
As can be seen from the equation, one molecule of 2-bromo-4-methylpropiophenone produces one molecule of mephedrone.
C10H11BrO : 227.0977 g/mol
C11H15NO : 177.2429 g/mol
227.0977/177.2429=1.28127953
The coefficient is 1.28127953
This means that from 100g of 2-bromo-4-propiophenone, you will get 78.0469818g of mephedrone base.

The mass of mephedrone hydrochloride will increase by 1.19 g/cm3 and the coefficient will be 1.27273446
C11H15NO+HCl=177.2429+1.19=178.4329
227.0977/178.4329=1.27273446

100g(C10H11BrO)/1.27273446=78.5709849g(C11H15NO)
The theoretical yield of the reaction of 2-bromo-4-methylpropiophenone was 78.5709849g mephedrone hydrochloride. But it should be considered that it is difficult to achieve the theoretical yield, usually the loss is 20%.
 
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Ba*****ka90

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I have found a supplier of 2-Bromo-4-Methylpropiophenone liquid but i dont know how to start from this point and how much liquid should i use to make 100g of 4mmc.I need some advices.
 

kaskaxldq

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To bych. I didn't. In a liquid. Good. Peppercorn
 

Tsigger

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I didn’t add acetone, just MMC freebase in benzene, and I dripped in 30% HCl at pH 5.5. I added the acid slowly. Could acetone be the issue? I forgot, because I usually acidify with DCM+water, so acetone didn’t come to mind. How did you acidify the beauty in the picture? Thank you very much.
 
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WillD

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If you use aq. hydrochloric acid, you need a solvent that binds water. This is acetone or alcohol (ethanol, propanol)
 

goatlabs666

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Thanks bro
 
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